Getting multiple outputs from a function?

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isa karaca
isa karaca 2019-3-31
评论： Guillaume 2019-3-31
Hi everyone. This is my code. It works well in this state but i want to change ''ord'' number from 1 to 4 and ''sfn'' number from 1 to ord+1. For example, when ord=3, sfn values should be 1, 2, 3 and 4, accordingly. How can i do this?
% shapefun( ord,sfn,x ) function gives the value of the 'sfn'th shape function of
% element with order 'order' at x coordinate.
% 'order' can be any integer above 0
% x € [-1,1]
% sfn is integers from 1 up to (order+1),
function result = shapefun(ord,sfn,x)
result=1;
if nargin==0
ord = 1;
sfn = 1;
x = linspace(-1,1,1000);
end
for i = 1:ord+1
if(i==sfn)
result = result.*1;
else
result = result.*(x-((i-1).*1./ord))./(((sfn-1).*1./ord)-((i-1).*1./ord));
end
end
end
  1 个评论
Guillaume
Guillaume 2019-3-31
Your code:
if(i==sfn)
result = result.*1;
Last I checked, multiplying by 1 doesn't do much. What is the point of that?

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回答（1 个）

Anish Navalgund
Anish Navalgund 2019-3-31
Hi Isa,
You can use switch statements to control your order and for each order you can have for loops to calculate for each sfn.
The psuedo code is below.
order = input('order= ');
switch order
case 1
for sfn = 1:2
result = shapefun(ord,sfn,x);
end
case 2
for sfn = 1:3
result = shapefun(ord,sfn,x);
end
end
And so on...
Hope this helps.
  6 个评论
显示 4更早的评论
Stephen23
Stephen23 2019-3-31
编辑：Stephen23 2019-3-31
"...my result matrix is being one row not two, i mean function take sfn as only 2 not both 1 and 2. Can you help about this case?"
Most likely you will need to use indexing on the output array, otherwise you simply discard the results of every iteration except for the last one. I say "most likely" as I do not understand your algorithm.
Anish Navalgund
Anish Navalgund 2019-3-31
@Isa, like @Stephen said you can use his method as the repetition of calling of the function is reduced. :)

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