Mean over specific columns
显示 更早的评论
Hi :)
I have a 450x42 table.
I would like to calculate the mean over cloumns 2:5 7:10 12:15 and so
mean([2:5],2) mean([7:10],2).....
anybody an idea :)
3 个评论
Walter Roberson
2019-3-31
Provided that the pattern keeps up:
squeeze( mean( reshape(Tab{:,setdiff(1:size(Tab,2),1:5:size(Tab,2))}, size(Tab,1), 4, []), 2))
Antonio Melieni
2019-3-31
Walter Roberson
2019-3-31
In the above, Tab would be your table object. All of the variables (columns) in the table would have to be numeric for it to work properly. The code I posted could have problems your variables are not all the same numeric type, such as if columns 2:5 were double but columns 7:10 were uint8.
回答（1 个）
John D'Errico
2019-3-31
编辑：John D'Errico
2019-4-1
Easy peasy? Convert to an array first of course. Or, if some of those columns are non-numeric, then convert only the indicated columns to an array.
But it is pretty easy to generate that list of columns.
T = rand(450,42);
M = mean(T(:,[2:5]' + (0:5:35)),1);
So the list of column indices is:
ind = reshape([2:5]' + (0:5:35),1,[]);
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
2019-3-31
2019-4-1
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
