How to solve 2 systems of linear equations with complex numbers

Question

Tawhid Khan 2019-4-1

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https://ww2.mathworks.cn/matlabcentral/answers/453752-how-to-solve-2-systems-of-linear-equations-with-complex-numbers

评论： Stephen Everett 2020-10-27

I am trying to solve these two equations where A and B are the variables:

A(-5E-4i)+B(.00166+5E-4i) = 0

A(.003+5E-4i)+B(-5E-4i)= .01

So far I tried this code but its not working:

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Answer 1

Matt J 2019-4-1

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https://ww2.mathworks.cn/matlabcentral/answers/453752-how-to-solve-2-systems-of-linear-equations-with-complex-numbers#answer_368501

编辑：Matt J 2019-4-1

在 MATLAB Online 中打开

There's no need to solve symbolically:

Matrix= [(-5E-4i),(.00166+5E-4i);...
         (.003+5E-4i),(-5E-4i)];
     
AB=Matrix\[0;0.01]

AB =
   3.1201 - 0.4558i
   0.3854 + 0.8237i

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Stephen Everett 2020-10-27

RIGHT ON!!!

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Answer 2

madhan ravi 2019-4-1

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/453752-how-to-solve-2-systems-of-linear-equations-with-complex-numbers#answer_368500

编辑：madhan ravi 2019-4-1

在 MATLAB Online 中打开

https://in.mathworks.com/help/symbolic/solve.html - single quotes were removed in the newer releases, the thing was to use syms to declare variables. The alternative is to use https://in.mathworks.com/help/matlab/ref/mldivide.html exactly as Matt showed below.

syms A B
e1 = A*(-5E-4i)+B*(.00166+5E-4i) == 0;
e2 = A*(.003+5E-4i)+B*(-5E-4i) == .01;
[A,B]=vpasolve(e1,e2)

Gives:

A =
 
3.1200854799813426046914748274026 - 0.45578296553343941143195508992931i
 
B =
 
0.38538768678070613609974428782671 + 0.82370415457850496041919594565537i