Info

此问题已关闭。 请重新打开它进行编辑或回答。

code with the same function

3 次查看（过去 30 天）
Gabriel Cunha
Gabriel Cunha 2019-4-3
关闭： MATLAB Answer Bot 2021-8-20
The code below gives me the right amount of how many times a letter repeats itself in a large text.txt.
I wanted another simple code, but that would do the same thing as this, in case it gave me the number of letters in a text (A = number of letters a, B = number of letters b and so on.)
if there is no simpler than this, accept another more complicated or the same level of difficulty.
fileread('mytextfile.txt')
data = fileread('mytextfile.txt');
nnz(data=='A')
nnz(ismember(data,'A'))

此问题已关闭。

回答（2 个）

Walter Roberson
Walter Roberson 2019-4-3
[A, ~, AA] = unique(data);
fprintf('%c = %d\n', [A, accumarray(AA, 1)].')
  8 个评论
显示 6更早的评论
Rik
Rik 2019-4-4
Despite of its name, char_list is already a double. I didn't notice your last edit with 0+A(:), so that is why that method is capped (as chars are capped to 16 bit).
Walter Roberson
Walter Roberson 2019-4-4
I did the 0+ after you (correctly) mentioned about the 65535.
Rik
Rik 2019-4-3
编辑：Rik 2019-4-4
There are two easy options: a loop and a histogram:
%for loop method:
data = fileread('mytextfile.txt');
letters='ABCDEFGHIJKLMNOPQRSTUVWXYZ';
counts=zeros(1,numel(letters));
for n=1:numel(letters)
counts(n)=nnz(data==letters(n));
end
%histogram method:
data = fileread('mytextfile.txt');
counts=histc(data,65:(65+25));
  4 个评论
显示 2更早的评论
Gabriel Cunha
Gabriel Cunha 2019-4-4
Your code is really incredible, but I also wanted something as simple as the code of my question that counted one letter at a time, but I will certainly study your code as well as the others who answered in order to learn more about MATLAB
Rik
Rik 2019-4-4
The edited for-loop method should be a bit easier to understand.

此问题已关闭。

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by