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Missing data values with interpolation

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Emmanuelle
Emmanuelle 2012-8-7
评论： mostafa mahdi yousef 2021-12-19
Hello everybody,
I have a cell array each containing a sequence of diferent values. The sequences contains some missing values (I've represented with NaN). I would like to replace all this NaN places with numbers. I think the better way is do an interpolation but I don't know how to code this Nan and how to save it on a table in Matlab.
I1= interp1(x,y,'linear');
Greetings,
Pd) I've tried this but it doesn't work
nanData = isnan(y);
index = 1:numel(y);
data2 = y;
data2(nanData) = interp1(index(~nanData), y(~nanData), index(nanData));

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-8-7
编辑：Azzi Abdelmalek 2012-8-7
x={ 1 2 3 4 5 6 7 8 9 10}
y={ 0.3850 NaN 3.0394 NaN 0.6475 1.0000 1.5000 NaN 1.1506 0.58}
x=cell2mat(x);y=cell2mat(y);
xi=x(find(~isnan(y)));yi=y(find(~isnan(y)))
result=interp1(xi,yi,x,'linear')
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Mritula C
Mritula C 2018-12-15
Hi, im facing the same issue. Can you explain what do you mean by " see ADD in my answer" ?

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更多回答（2 个）

Steven Lord
Steven Lord 2018-12-15
If you're using release R2016b or later you can use the fillmissing function.
Andrei Bobrov
Andrei Bobrov 2012-8-7
编辑：Andrei Bobrov 2012-8-8
eg
data
Data = cell(1,5);
for jj = 1:5
k = [randi(250,randi([10,15]),1); nan(randi([0 3]),1) ];
Data{jj} = k(randperm(numel(k)));
end
solution
for jj = 1:numel(Data)
n = (1:numel(Data{jj}))';
k = ~isnan(Data{jj});
Data{jj} = interp1(n(k),Data{jj}(k),n,'linear','extrap');
end
ADD
load doc1.txt
x = doc1(:,1);
y= doc1(:,2);
t = all(~isnan([x,y]),2);
out = interp1(x(t),y(t),x,'linear','extrap');

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