"if" function with cell array

6 次查看（过去 30 天）
Matthew Covington
评论： Rik 2019-4-6
I am using the following code:
for n = 1:numbers_rows %numbers_rows = 32
if words{n, 3} == 's'
fprintf('%02.0f/%02.0f/%d ', numbers(n, 1), numbers(n, 2), numbers(n, 3))
fprintf('%s\n', words{n,2})
end
end
and getting the following output:
Date Opponent
01/10/2019 Tennessee
01/14/2019 Florida
01/17/2019 Alabama
01/24/2019 Mississippi State
01/27/2019 Vanderbilt University
01/31/2019 Texas A&M
02/03/2019 Mizzou
02/07/2019 Ole Miss
02/10/2019 Georgia
02/14/2019 Kentucky
02/17/2019 Arkansas
02/24/2019 Tennessee
02/28/2019 Alabama
03/03/2019 Missouri
03/07/2019 South Carolina
03/08/2019 LSU
03/23/2019 ALABAMA
The ouput I am looking for is:
01/03/2019 Tennessee
01/06/2019 Florida
01/10/2019 Alabama
01/14/2019 Mississippi State
01/17/2019 Vanderbilt University
01/24/2019 Texas A&M
01/27/2019 Mizzou
01/31/2019 Ole Miss
02/03/2019 Georgia
02/07/2019 Kentucky
02/10/2019 Arkansas
02/14/2019 Tennessee
02/17/2019 Alabama
02/24/2019 Missouri
02/28/2019 South Carolina
03/03/2019 LSU
03/07/2019 ALABAMA
03/08/2019 TEXAS A&M
As you can tell, the dates and opponents do not match up. Im not sure what Im doing wrong. The data that was extracted is attacthed. I extracted it using xlsread() as I was instraucted to do. Also this is where numbers_rows comes from in the for loop
[numbers, words, everything] = xlsread(FILENAME);
[numbers_rows, numbers_columns] = size(numbers);
  2 个评论
Matthew Covington
Matthew Covington 2019-4-5
I figured it out my mistakes, my bad
Rik
Rik 2019-4-6
Then you should either post the solution, or delete the question.

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