1D array values to 2D matrix
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I would like to 'convert' a 1D array to a 2D matrix considering the value inside the array as:
A =
1 3 5 4 3
B =
1 3 5 4 3
0 3 5 4 3
0 3 5 4 3
0 0 5 4 0
0 0 5 0 0
Can you suggest a fast way to do that?
采纳的回答
Adam Danz
2019-4-8
A for-loop would make a cleaner read (I could provide that upon request) but here's two lines the do the trick.
base = cellfun(@(x)repmat(x,x,1), num2cell(A), 'UniformOutput', false);
cell2mat(cellfun(@(y,n) padarray(y,n, 'post'),base, num2cell(max(A)-A), 'UniformOutput', false))
ans =
1 3 5 4 3
0 3 5 4 3
0 3 5 4 3
0 0 5 4 0
0 0 5 0 0
6 个评论
Eduardo Santos
2019-4-9
Eduardo Santos
2019-4-9
Adam Danz
2019-4-9
Your solution above is one way to do it. If you don't need the original matrix in the first place and want to bypass that,
% |-------| This is the only change
base = cellfun(@(x)ones(x,1), num2cell(A), 'UniformOutput', false);
cell2mat(cellfun(@(y,n) padarray(y,n, 'post'),base, num2cell(max(A)-A), 'UniformOutput', false))
Eduardo Santos
2020-12-24
A = [1,3,5,4,3]
B = zeros(max(A),numel(A));
for i = 1:numel(A)
B(1:A(i),i) = 1:A(i);
end
disp(B)
Eduardo Santos
2021-1-4
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