Convert number to string problem

I would like to ask if there is a way to output a number, which is stored as a variable, using simple commands, as shown in the following examples:
9 is converted to: 'The number is +9.'
6.54 is converted to: 'The number is +6.54.'
-7 is converted to: 'The number is -7.'
-9.2 is converted to: 'The number is -9.2.'
0 is converted to: 'The number is 0.'
I would like to display it in the command window and a message box (msgbox).
Please help. Thanks in advance.

 采纳的回答

number = 10; % an example
if number>=0
sprintf('The number is : +%d',number)
else
sprintf('The number is : %d',number)
end
Assign a variable to sprintf() and then place it inside the command msgbox().

5 个评论

Sorry, what is %d? Why it isn't %g?
If I want to display more than one numbers, such as:
a=9,b=8,c=0,d=-5,e=-6 (Not necceaasry in descending order.)
'The numbers are +9,+8, 0, -5 and -6 respectively.'
I have tried to do this, but its very long winded, and if there are 10 of them, it would get to thousands of lines. Any suggestions?
Well, the first problem is that you use a different variable for each number instead of putting them all into a single array.
If the numbers were stored in a single array, your question is trivially solved in many ways. One way:
numbers = [9, 8, 0, -5, -6];
fprintf('The numbers are %s respectively.\n', strjoin(compose('%+d', numbers), ', '));
Thank you Guillaume, Stephen’s solution looks good but anyways let me give my suggestion too, use logical indexing group according to positive and negative numbers and use sprintf() all at once.

请先登录,再进行评论。

更多回答(1 个)

Stephen23
Stephen23 2019-4-10
编辑:Stephen23 2019-4-10
>> V = [9,8,0,-5,-6]; % your data should be in one array.
>> S = sprintf(', %+g',V(1:end-1));
>> S = sprintf('The numbers are%s and %+g respectively',S(2:end),V(end))
S = 'The numbers are +9, +8, +0, -5 and -6 respectively'
˜>> regexprep(S,'\+0([, ])','0$1') % if you don't like '+0'
ans = 'The numbers are +9, +8, 0, -5 and -6 respectively'

类别

帮助中心File Exchange 中查找有关 Characters and Strings 的更多信息

产品

版本

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by