How do I specify the cell array to indicate strings in double quotation?

2019 4 12
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更新时间：2019 4 12
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I have an array of strings (pulled from Excel column headers).
For example,
A{1,1} = 'Station Number'
A{1,2} = 'Depth'
etc.
How do I specify the array, so that the output is (please note the double quotation)'
"Station Number"
"Depth"
etc.
The reason I want double quotation is to use the newline function.
Thank you.

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 采纳的回答

Star Strider
Star Strider 2019-4-12

0 个投票

Use the string (link) function:
A{1,1} = 'Station Number'
A{1,2} = 'Depth'
A = string(A)
producing:
A =
1×2 cell array
{'Station Number'} {'Depth'}
A =
1×2 string array
"Station Number" "Depth"
So ‘A’ begins as a cell array and after the conversion becomes a string array.
Is that what you want to do?

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Leon
Leon 2019-4-12
Exactly what I want! Thank you very much.
Leon
Leon 2019-4-12
编辑：Leon 2019-4-12
Can you help me find the bug of my code?
AA = [];
for i = 1:length(E)
AA = [AA +newline+ string(B{1,E(i)}) ];
end
app.text.Value = AA;
There are some extra preceding 10s in the final results. What is causing this?
10Temp_1_Flag
10Temp_2
10Temp_2_Flag
10Sal_2
10Sal_2_Flag
It should be like this:
Temp_1_Flag
Temp_2
Temp_2_Flag
Sal_2
Sal_2_Flag
Star Strider
Star Strider 2019-4-12
编辑：Star Strider 2019-4-12
I don’t have enough information.
What are ‘AA’, ‘B’, and ‘E’? (I need to test your code to see if I can find out what’s wrong. I only need a few values, not the entire array.)
EDIT —
I can’t run your code without your data to test it with. However the spacing in the vector is likely an issue.
Try this instead:
AA = [AA + newline + string(B{1,E(i)}) ];
Also see if the compose (link) function will do what you want. You might be able to avoid the loop entirely.
Experiment to get the result you want.
Leon
Leon 2019-4-12
编辑：Leon 2019-4-12
Thank you!
Attached is my Excel file example.
[A, B, C] = xlsread (example.xlsx);
B = B(1,:);
E = [1;2;3];
AA = [];
for i = 1:length(E)
AA = [AA +newline+ string(B{1,E(i)}) ];
end
app.text.Value = AA;
I'm writing the code under Matlab app designer, BTW.
Leon
Leon 2019-4-12
After changing it to the below, it is working perfectly now. I really appreciate your help!
AA = [AA newline B{1,E(i)}];

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