Mean value of array

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Chihiro Omori
Chihiro Omori 2019-4-12
编辑: Guillaume 2019-4-12
I need to calculate the mean of [1 2 ; 9 10],[2 3 ; 10 11] [3 4 ; 11 12] ,[4 5 ; 12 13] ....and make 3*7 matrix of the mean values of A(=4*8 matrix).
Does anyone has idea how to make it?
A=[1 2 3 4 5 6 7 8 ;
9 10 11 12 13 14 15 16;
17 18 19 20 21 22 23 24;
25 26 27 28 29 30 31 32]
  3 个评论
Chihiro Omori
Chihiro Omori 2019-4-12
I would like the output below.
A_mean = [5.5, 6.5, 7.5, 8.5, 9.5, 10.5, 11.5;
13.5 14.5, 15.5, 16.5, 17.5, 18.5, 19.5;
21.5, 22.5, 23.5, 24.5, 25.5, 26.5, 27.5]
The first row represents that ... 5.5 = ((1+2+9+10)/4) , 6.5 = ((2+3+10+11)/4), ...
The second row represents ... 13.5 = ((9+10+17+18)/4), ......
Guillaume
Guillaume 2019-4-12
You've been given two methods to achieve that output.

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采纳的回答

Guillaume
Guillaume 2019-4-12
编辑:Guillaume 2019-4-12
Trivially solved with a convolution
A=[1 2 3 4 5 6 7 8 ;
9 10 11 12 13 14 15 16;
17 18 19 20 21 22 23 24;
25 26 27 28 29 30 31 32]
conv2(A, ones(2)/4, 'valid') %comvolve with [0.25, 0.25; 0.25, 0.25]

更多回答(1 个)

KSSV
KSSV 2019-4-12

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