Create a Matrix with Specific Pattern for Changing Values

2019 4 16
1 个回答
更新时间：2019 4 16
4 次查看（30 天）

0 个投票

How can I create a matrix such as this one where the change in value is some dx and each column varies differently?
[-3*pi/4 -3*pi/4 -3*pi/4;
-3*pi/4 -3*pi/4 -3*pi/8;
-3*pi/4 -3*pi/4 0;
-3*pi/4 -3*pi/8 -3*pi/4;
-3*pi/4 -3*pi/8 -3*pi/8;
-3*pi/4 -3*pi/8 0;
-3*pi/4 0 -3*pi/4;
-3*pi/4 0 -3*pi/8;
-3*pi/4 0 0;
-3*pi/8 -3*pi/4 -3*pi/4;
-3*pi/8 -3*pi/4 -3*pi/8;
-3*pi/8 -3*pi/4 0;
-3*pi/8 -3*pi/8 -3*pi/4;
-3*pi/8 -3*pi/8 -3*pi/8;
-3*pi/8 -3*pi/8 0;
-3*pi/8 0 -3*pi/4;
-3*pi/8 0 -3*pi/8;
-3*pi/8 0 0;
0 -3*pi/4 -3*pi/4;
0 -3*pi/4 -3*pi/8;
0 -3*pi/4 0;
0 -3*pi/8 -3*pi/4;
0 -3*pi/8 -3*pi/8;
0 -3*pi/8 0;
0 0 -3*pi/4;
0 0 -3*pi/8;
0 0 0]

请先登录，再回答此问题。

回答（1 个）

Kelly Kearney
Kelly Kearney 2019-4-16

1 个投票

Create a grid of values, then unwrap:
xval = [-3*pi/4 -3*pi/8 0];
[a,b,c] = ndgrid(x,x,x);
x = [c(:) b(:) a(:)]

类别

在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by