Extract Previous Cell Value

2019 4 21
1 个回答
更新时间：2019 4 23
5 次查看（30 天）

0 个投票

I have a cell with char values next to each other as seen below
Cell 1 | Cell 2
____________
'Hello' | 'World'
I would like to define a function that extracts the previous cell value along with the current cell value. I wrote the following code to do so:
t = x{1,i} - Current Cell Value
f = x{2,i-1} - Previous Cell Value, starting with Cell 2 with the previous value of Cell 1
But I keep getting the error
Index in position 2 is invalid. Array indices must be positive integers or logical values.
I believe the error is with regards to the defined function f. It has to do with the i-1 value. At this point, I am stuck. Any thoughts on how to fix that so it works?

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回答（1 个）

TADA
TADA 2019-4-21
编辑：TADA 2019-4-21

0 个投票

The problem is you're indexing at index 0 which is invalid.
% some specific handling of
% the first cell should be
% executed here if necessary
for i = 2:size(x,2)
t = x{1,i};
f = x{2,i-1};
end

6 个评论
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Jeffrey Pang
Jeffrey Pang 2019-4-21
Its now telling me
Index exceeds array bounds.
TADA
TADA 2019-4-21
I'll have to see your code and an example of the data to know what's going on
Jeffrey Pang
Jeffrey Pang 2019-4-21
I am trying to make a card game where you draw cards until you get 2 in a row (2 kings are drawn one after the other) . The feature I am trying to implement is to stop the code when two cards of the same type are drawn.
Code:
deck = {char('2 Spades'), char('2 Hearts'), char('2 Clubs'), char('2 Diamonds'), char('3 Spades'), char('3 Hearts'), char('3 Clubs'), char('3 Diamonds'), char('4 Spades'), char('4 Hearts'), char('4 Clubs'), char('4 Diamonds') , char('5 Spades'), char('5 Hearts'), char('5 Clubs'), char('5 Diamonds'), char('6 Spades'), char('6 Hearts'), char('6 Clubs'), char('6 Diamonds'), char('7 Spades'), char('7 Hearts'), char('7 Clubs'), char('7 Diamonds'), char('8 Spades'), char('8 Hearts'), char('8 Clubs'), char('8 Diamonds'), char('9 Spades'), char('9 Hearts'), char('9 Clubs'), char('9 Diamonds'), char('10 Spades'), char('10 Hearts'), char('10 Clubs'), char('10 Diamonds'), char('K Spades'), char('K Hearts'), char('K Clubs'), char('K Diamonds'), char('J Spades'), char('J Hearts'), char('J Clubs'), char('J Diamonds'), char('Q Spades'), char('Q Hearts'), char('Q Clubs'), char('Q Diamonds'), char('A Spades'), char('A Hearts'), char('A Clubs'), char('A Diamonds')};
x = randsample(deck, 52, false);
for i = 1:52;
pause(1)
disp(x{1,i});
for j = 2:size(x,2)
t = x{1,j};
f = x{2,j-1};
end
if t(1) == f(1)
pause
end
reshape([deck],1,[]);
end
TADA
TADA 2019-4-21
编辑：TADA 2019-4-21
This is your problem
f = x{2,j-1};
As x is a one dimentional row cell array
This should work I think:
for i = 1:52
disp(x{1,i});
t = x{1,i};
f = x{1,i-1};
if t(1) == f(1)
break;
end
end
Jeffrey Pang
Jeffrey Pang 2019-4-23
I got it. Thank you for putting me on the right track!
TADA
TADA 2019-4-23
Cheers
Good luck

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TADA
TADA
2019-4-23

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