Solving Integrals with MATLAB
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I am stuck on one of the problems i am working on. Could anyone tell me how to write a code for this problem? Using the quadl and the int command.
Problem: f(x)=integral sign(1+5/1+x^2)dx
upper bound is 1
lower bound is 0
4 个评论
madhan ravi
2019-4-22
What have we tried? Read the documentation of integral().
Walter Roberson
2019-4-22
x^2 cannot be negative for real x, but could be 0.
Adding 1 and (5/1) to that gives you 6+x^2, and for real x that has a mininum value of 6 -- always positive.
sign() of an always-positive value is always 1.
Therefore you are taking the integral of the constant 1 over a range. The indefinite integral of that is x, so the definite integral is (upperbound minus lowerbound), 1 - 0, for a total of 1.
Therefore the value of your integral is 1.
David Wilson
2019-4-22
I interpreted it as "integral_sign", not integral ( sgn(...) dx).
KALYAN ACHARJYA
2019-4-22
编辑：KALYAN ACHARJYA
2019-4-22
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