Adding new field to structure array

8 次查看（过去 30 天）
Maciej Grybko
Maciej Grybko 2019-4-22
评论： Maciej Grybko 2019-4-22
I have a structure vector s with already existing fields f1 and f2. I want to perform calculations on those fields for every single element and save results to a new field f3. Can following expressions be simplified?
fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2])
a = num2cell(a)
[s.f3] = a{:}

请先登录，再回答此问题。

采纳的回答

Maciej Grybko
Maciej Grybko 2019-4-22
编辑：Maciej Grybko 2019-4-22
Okay, I figured it out:
fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2], 'UniformOutput',false)
[s.f3] = a{:}
But still, is there any way to combine 2nd and 3rd line?

更多回答（1 个）

Walter Roberson
Walter Roberson 2019-4-22
编辑：Walter Roberson 2019-4-22
Not really. You could reduce by one line by using
a = num2cell(arrayfun(fun, [s.f1], [s.f2]));
for whatever that is worth.
You could go through struct2cell() and create a new cell with the result, but it is not going to be any simpler than what you already have.
You could do it in fewer lines using especially obscure syntax. I am the only person whom I have seen use that syntax in about a decade -- I posted an example a few months ago just to prove that it could be done -- and that it was not worth doing. It would not be any simpler: it would leave even fairly advanced MATLAB users scratching their heads and wondering, "Can you do that???"
  6 个评论
显示 4更早的评论
madhan ravi
madhan ravi 2019-4-22
;) knew it , thank you sir Walter.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by