Adding new field to structure array
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I have a structure vector s with already existing fields f1 and f2. I want to perform calculations on those fields for every single element and save results to a new field f3. Can following expressions be simplified?
fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2])
a = num2cell(a)
[s.f3] = a{:}
采纳的回答
Maciej Grybko
2019-4-22
编辑：Maciej Grybko
2019-4-22
1 个评论
madhan ravi
2019-4-22
Isn’t that what Alex posted 30 minutes earlier to this?
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Walter Roberson
2019-4-22
编辑：Walter Roberson
2019-4-22
Not really. You could reduce by one line by using
a = num2cell(arrayfun(fun, [s.f1], [s.f2]));
for whatever that is worth.
You could go through struct2cell() and create a new cell with the result, but it is not going to be any simpler than what you already have.
You could do it in fewer lines using especially obscure syntax. I am the only person whom I have seen use that syntax in about a decade -- I posted an example a few months ago just to prove that it could be done -- and that it was not worth doing. It would not be any simpler: it would leave even fairly advanced MATLAB users scratching their heads and wondering, "Can you do that???"
6 个评论
Alex Mcaulley
2019-4-22
Another option (I don't know which is more efficient):
fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2],'UniformOutput',false);
[s.f3] = a{:}
Walter Roberson
2019-4-22
That's a good approach.
madhan ravi
2019-4-22
Sir Walter is that possible using substruct() and subsasgn() ? It would be nice if it’s possible.
Walter Roberson
2019-4-22
Yes, using subsasgn() is the very obscure syntax I was referring to.
madhan ravi
2019-4-22
;) knew it , thank you sir Walter.
Maciej Grybko
2019-4-22
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