error using contains function
显示 更早的评论
when I use contains function in a loop it show me that error message, even though Raw is a cell array, and also the compilation complete and the code after if contains(Raw(i,2),serie)==1 works well.
is there a solution for that ?
5 个评论
AMINE EL MOUATAMID
2019-4-22
AMINE EL MOUATAMID
2019-4-22
You need to provide the variables (in a .mat file) that would let us run the important section of the code as follows:
load yourMATFile.mat
sizeRaw=size(Raw);
for i=2 : sizeRaw(1,1)
if contains(Raw(i,2),serie)==1
for j=2 : rowRMS(1,1)
if contains(Raw(i,1),RMS(j,1))==1
if contains(Raw(i+1,8),MeasTypeID)==1
Raw(i+1,9)=RMS(j,2);
else
if contains(Raw(i+2,8),MeasTypeID)==1
Raw(i+2,9)=RMS(j,2);
else
if contains(Raw(i+3,8),MeasTypeID)==1
Raw(i+3,9)=RMS(j,2);
end
end
end
end
end
end
end
AMINE EL MOUATAMID
2019-4-22
采纳的回答
I can see in your screen shot of workspace variables that your "Raw" array contains mostly NaN values.
According to your error message, the first argument of contains() must be a string array, char vector, or cell array of char vectors. "Raw" appears to be a cell array with lots of NaNs.
You probably want to just skip iterations where the input to contains() includes NaN values (or you might want to use a different method).
5 个评论
AMINE EL MOUATAMID
2019-4-22
Adam Danz
2019-4-22
Yep! One way to avoid iterations with NaNs is something like this:
if all(~isnan(Raw(i,1))) & contains(Raw(i,1),RMS(j,1))==1
AMINE EL MOUATAMID
2019-4-22
You need to do some exploring. Some trial and error. The error message tells you that the input to isnan() does not accept cell arrays. So try this
isnan(out{2,2})
% or
isnan([out{2,2}])
More more information on how to work with cell arrays:
AMINE EL MOUATAMID
2019-4-22
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
