How to turn a large array into multiple smaller arrays

12 次查看（过去 30 天）
Lori
Lori 2012-8-12
评论： k 2020-7-17
Hi,
I have an array that has 31 rows and 1518 columns. I'm trying to figure out a quick way to turn that array into 759 arrays that are 31 rows and 2 columns. I want to take the first two columns, then the next two columns, etc. I was wondering this there was a way to do this in a loop, but was unsure if you could create and name new arrays in a loop. Any help would be much appreciated!
Thanks,
Lori
  1 个评论
Oleg Komarov
Oleg Komarov 2012-8-13
Please, do not post duplicate questions. Also, do not create incremental variables by splitting your array. It's a design suicide and bad programming practice.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（3 个）

Wayne King
Wayne King 2012-8-12
编辑：Wayne King 2012-8-12
I think you want to store the separate matrices in a cell array rather than having 759 separate matrices, right? I mean you can always just access each of the 31x2 matrices from the cell array
X = randn(31,1518);
k = 1;
for nn = 1:2:1518-1
Y{k} = X(:,nn:nn+1);
k = k+1;
end
Now you can access each of the 31x2 matrices as
Y{1}, Y{2}, etc.
  1 个评论
k
k 2020-7-17
Hi! Is there a way to add to this loop a way for the program to plot every Y{} matrix, potentially in the same layout via tiledlayout()?

请先登录，再进行评论。

Azzi Abdelmalek
Azzi Abdelmalek 2012-8-12
编辑：Azzi Abdelmalek 2012-8-13
A=rand(31,1518); %example
B=reshape(A,31,2,1518/2)
for k=1: 1518/2
out.(sprintf('A%d',k))=B(:,:,k)
end
the first array is
out.A1,
thee second is
out.A2 ,
the last
out.A759
Andrei Bobrov
Andrei Bobrov 2012-8-13
out1 = reshape(yourmatrix,size(yourmatrix,1),2,[]);
or
out2 = mat2cell(yourmatrix,size(yourmatrix,1),2*ones(size(yourmatrix,2)/2,1));

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by