Script that calculates the following sum

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Juan Zegarra
Juan Zegarra 2019-4-28
回答： Jan 2019-4-29
Write a script that will calculate the convertage series of S= starting at n=0. This series will converge on S=2. That is 1/1 +1/2 +1/4.... The script will terminate whn 2 >S>=1.990 and it will print a sentence that contains the values for S and n. I've done this so far but I'm getting errors. Can you please help me?\
n=0
S=0
while S > 1.990
S=1/(2^n)+S
n=n+1
S(n)=S
end

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回答（1 个）

Jan
Jan 2019-4-29
n=0
S=0 % Now S is a scalar
while S > 1.990 % In the first iteration you compare a scalar
% But you do not mean >, but <= !
S=1/(2^n)+S
n=n+1
S(n)=S % If n=2, you assign: S(2)=S, but for n=3:
% it is: S(3) = S and S is a [1 x 2] vector
end
Store the current value of S in a separate variable, e.g. SV, which is a vector then.

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