NaN with backslash operator

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Sun
Sun 2019-4-29
编辑： Sun 2019-7-31
Hi,
I would like to understand the reason as to why the below operation is giving a NaN solution for the attached data.
x = A\B;
Thank you.
YK..

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采纳的回答

Adam Danz
Adam Danz 2019-4-29
The following rows of your variable "B" contain NaN values.
find(isnan(B))
ans =
1491
1492
1493
1494
1495
1496
1497
To ignore the NaN values,
nanIdx = isnan(A) | isnan(B);
A(~nanIdx) \ B(~nanIdx)
ans =
-0.091457
  2 个评论
John D'Errico
John D'Errico 2019-4-29
The problem being that NaNs propagate. Everything they touch, turns to NaN. (Like old King MIdas, but in an even worse way.) So if you already have NaNs in your data, give it up. You need to excise them from your data before any linear algebra computations.
Steven Lord
Steven Lord 2019-4-29
FYI the functions listed in the "Missing Data and Outliers" section of this documentation page may be of use in locating, removing, and/or replacing the NaN values in the data.

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