element wise logical operators?
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I have a question regarding using logical operators on a multi-dimensional array.
I want to firstly test if an element passes a criteria then replace that value with another value given the results of a test.
I want to check the first dimension of the array against the threshold of 0.5 and replace all instances where this is true with a value for only 2 columns of the the 2nd dimension and all cases of the 3rd and 4th dimension. Does anyone know how to do this without multiple for loops?
for example
DA = rand(4,4,2,3);
if DA(:,2:4,:,:)<0.5;
DA(:,2:4,:,:) = 1;
end
thanks Tim
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Azzi Abdelmalek
2012-8-14
编辑:Azzi Abdelmalek
2012-8-14
clear
DA = rand(4,4,2,3);
K=arrayfun(@(x) x<0.5,DA(:,2:4,:,:))
B=DA(:,2:4,:,:);
B(find(K==1))=1;
DA(:,2:4,:,:)=B
1 个评论
per isakson
2012-8-14
编辑:per isakson
2012-8-14
Explicitly operating on a sub array and assign it back is a good approach. However, may I propose a bit of refactoring according to Matt Fig above:
sub_array = DA(:,2:4,:,:);
sub_array( sub_array < 0.5 ) = 1;
DA(:,2:4,:,:) = sub_array;
更多回答(2 个)
Matt Fig
2012-8-13
编辑:Matt Fig
2012-8-14
Do you mean this?
DA = rand(4,4,2,3);
DA(DA(:,2:4,:,:)<0.5) = 1;
or perhaps you are talking about this (see the comments below):
DA = rand(4,4,2,3);
tmp = DA(:,2:4,:,:);
tmp(tmp<.5) = 1;
DA(:,2:4,:,:) = tmp;
3 个评论
per isakson
2012-8-14
编辑:per isakson
2012-8-14
It turned out, I cannot make sense of the question. OP must help.
However, I found it very hard to grasp
M( logical_index ) = scalar;
when size(M) is not equal to size(logical_index). One dimension is ok, but four is not.
Is there a way to think about it?
OK, now I got the message: Work with sub arrays!
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