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Is it available to change the end of a loop for inside it?

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AMINE EL MOUATAMID
AMINE EL MOUATAMID 2019-4-30
回答： NALLARASU KRISH 2023-5-30
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the size of my variable out changes inside the loop for so that's why I recalculate it inside it but the loop variable i stops in the first size of the variable even sizeOut changes.
can't the endval of the loop change ? or it can't ?
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Adam Danz
Adam Danz 2019-4-30
The break would be conditional upon the size of sizeOut. In other words,
if sizeOut(1,1) == something
break
end
AMINE EL MOUATAMID
AMINE EL MOUATAMID 2019-4-30
I understand but sizeOut(1,1) maybe stay in the first value and maybe changes so I can't test it with something to break the loop.
otherways the while loop is better

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采纳的回答

Adam Danz
Adam Danz 2019-4-30
编辑：Adam Danz 2019-4-30
You want to use a while loop for this purpose.
It might look something like this (tough to tell without seeing more of your code)
c = 2; %counter
while c <= sizeOut(1,1)
% Do something
c = c+1;
end
Another good suggestion by Stephen Cobeldick is to add a conditional break to the for-loop that exits the loop when the sizeOut variable reaches a certain size.
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Adam Danz
Adam Danz 2019-4-30
编辑：Adam Danz 2019-4-30
A for-loop is designed to be executed a fixed number of times and once you enter the loop you cannot change the number of expected iterations. The only options are to conditionally break to leave the loop early or to continue to skip an iteration.
A while loop, on the other hand, is designed to continually iterate until a condition is met (break and continue are also options).

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更多回答（1 个）

NALLARASU KRISH
NALLARASU KRISH 2023-5-30
In MATLAB, end condition of a for loop cannot be updated or changed within the for loop. Once it is set during the start of the loop, it is set until it is met.
a = 1;
b = 6;
for c = a+1 : b
c
b
fprintf('here\n');
b = b-1;
end
After seeing the above code, one might think that "here" is printed only three times. But MAT thinks otherwise.
c =
2
b =
6
here
c =
3
b =
5
here
c =
4
b =
4
here
c =
5
b =
3
here
c =
6
b =
2
here

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