round function on complex numbers

2019 4 30
1 个回答
更新时间：2019 4 30
4 次查看（30 天）

0 个投票

So I have entered a complex array like this
a = [1,1,1,1; 1 -j -1 -1; 1 -1 1 -1; 1 j -1 -j]
And get output as
a =
1.0000 + 0.0000i 1.0000 + 0.0000i 1.0000 + 0.0000i 1.0000 + 0.0000i
1.0000 + 0.0000i 0.0000 - 1.0000i -1.0000 + 0.0000i -1.0000 + 0.0000i
1.0000 + 0.0000i -1.0000 + 0.0000i 1.0000 + 0.0000i -1.0000 + 0.0000i
1.0000 + 0.0000i 0.0000 + 1.0000i -1.0000 + 0.0000i 0.0000 - 1.0000i
which is fine.
But I want to round this array to show complex numbers as integers. Eg 1 + 0i, 1+ i etc. How do I achieve this?
round() function doesnt seem to do anything as
>> round(a)
ans =
1.0000 + 0.0000i 1.0000 + 0.0000i 1.0000 + 0.0000i 1.0000 + 0.0000i
1.0000 + 0.0000i 0.0000 - 1.0000i -1.0000 + 0.0000i -1.0000 + 0.0000i
1.0000 + 0.0000i -1.0000 + 0.0000i 1.0000 + 0.0000i -1.0000 + 0.0000i
1.0000 + 0.0000i 0.0000 + 1.0000i -1.0000 + 0.0000i 0.0000 - 1.0000i

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回答（1 个）

Stephen23
Stephen23 2019-4-30
编辑：Stephen23 2019-4-30

1 个投票

This has nothing to do with rounding. Either change the format, e.g.:
>> format short g
>> a = [1,1,1,1; 1 -j -1 -1; 1 -1 1 -1; 1 j -1 -j]
a =
1 1 1 1
1 0 - 1i -1 -1
1 -1 1 -1
1 0 + 1i -1 0 - 1i
Or write your own display code using fprintf, e.g.:
>> fmt = [repmat(' %d%+di',1,size(a,2)),'\n'];
>> fprintf(fmt,a.')
1+1i 1+1i 1+0i -1-1i
1-1i 1-1i 1+0i -1+0i

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