How to randomly swap 2 elements in an array?
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Suppose that I have the below array:
C= [1 6 5 10 1 2 11 8 2 7 3 7 9 9]
How can I swap randomly only the elements inside the bold numbers
Assume after swap 11 and 3 : C= [1 6 5 10 1 2 3 8 2 7 11 7 9 9]
or swap 10 and " " between 9 9: C= [1 6 5 1 2 11 8 2 7 3 7 9 10 9]
采纳的回答
I'm going to assume at least one of the swap elements must be an number, and that the swapped numbers are allowed to have the same value (so you can some one 9 with another 9).
C= [1 6 5 10 1 2 11 8 2 7 3 7 9 9];
bold=[1 5 6 9 10 12 13 14];
C_temp=cell(1,2*numel(C));
C_temp(2:2:end)=num2cell(C);
valid_idx=1:numel(C_temp);
valid_idx(bold*2)=[];
swap_idx=[1 1];%invalid output to enter the loop
while ~any(mod(swap_idx,2)==0) || ... %at least 1 needs to be a number
swap_idx(1)==swap_idx(2) %the indices must be different
swap_idx=valid_idx(randperm(numel(valid_idx),2));
end
%perform swap
C_temp(swap_idx)=C_temp(swap_idx(end:-1:1));
D=cell2mat(C_temp);
clc,disp(C),disp(D)
12 个评论
Thank you! but can you make it more flexible? I got C from ramdomly displayed.
So these bold numbers are not in the fit position.
And your code display this when I run:
1 6 5 10 1 2 11 8 2 7 3 7 9 9
6 1 5 10 1 2 11 8 2 7 3 7 9 9
6 is out of 1 1
You didn't describe how you get the bold numbers, so you'll have to figure that out from your input. I might be able to help you there, but I can't read your mind.
Your output should not be possible, that is what the while loop is for. What do the two conditions return if you try them on their own?
it showed this when I run:
C =
1 6 5 10 1 2 11 8 2 7 3 7 9 9
swap_idx =
23 15
swap_idx =
21 3
swap_idx =
11 25
swap_idx =
1 4
6 1 5 10 1 2 11 8 2 7 3 7 9 9
this is how I got C:
I have D = [170, 80, -30, 0, -50, -30, 20, -60, 100, -60 -20];
A contains all + elements and I repelem them( those bold number)
B contains all - elements
Then I randomly put B into A to create C.
Now I want to swap elements between bold numbers
I don't really understand what you mean in your description. At any rate, you should be able to write some code that returns a vector with which elements are bold.
About the result you had the first point: before the first number element there is an empty cell where swapping is allowed. If you don't want that, you can put in an extra condition in the while statement:
while ~any(mod(swap_idx,2)==0) || ... %at least 1 needs to be a number
swap_idx(1)==swap_idx(2) || ... %the indices must be different
any(swap_idx==1) %the first element (1 before the first number) isn't allowed
swap_idx=valid_idx(randperm(numel(valid_idx),2));
end
yes, thank you so much for yor time!
I am sorry for bothering you, but I wonder why sometimes the result is still the same after swapping:
C =
1 6 5 10 1 2 11 8 2 7 3 7 9 9
swap_idx =
23 9
swap_idx =
4 3
1 6 5 10 1 2 11 8 2 7 3 7 9 9
Look at the indices being swapped. What do you think is happening?
It was invalid then it swaps again, but most of the time it returns the same array.
Look at the indices. What is being swapped if they are 4 and 3?
I got it, it's nothing at 3 and number 6 at 4. Thank you! I will try to fix it!
This should prevent the two swapped values to be adjacent (which swaps a value with a gap, meaning it seems the array stays the same).
while ~any(mod(swap_idx,2)==0) || ... %at least 1 needs to be a number
any(swap_idx==1) || ... %the first element (1 before the first number) isn't allowed
abs(diff(swap_idx))<=1 %the indices must be different and more than 1 appart
swap_idx=valid_idx(randperm(numel(valid_idx),2));
end
Thank you for the help!
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