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Short code for the expression

2 次查看（过去 30 天）
Tino
Tino 2019-5-1
评论： Guillaume 2019-5-1
h =2;
P = [1, 4, 5, 7];
a1 = (1-h)* 1 + h * P(:, 1);
a2 = (1-h) * a1 + h * P(:, 2);
a3 = (1-h) * a2 + h * P(:, 3);
a4 = (1-h) * a3 + h * P(:, 4);
disp(a1) = 1
disp(a2) = 7
disp(a3) = 3
disp(a4) = 11
  2 个评论
Tino
Tino 2019-5-1
Please I will appreciate the answer to this question
thanks in advance
Guillaume
Guillaume 2019-5-1
To what question? You haven't asked anything, just given us some code with no explanation nor context.

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采纳的回答

madhan ravi
madhan ravi 2019-5-1
编辑：madhan ravi 2019-5-1
a = num2cell( (1-h) * repmat( (1-h) * 1 + h * P(1), 1, 4) + h * P ) ;
[a1, a2, a3, a4] = deal( a{:} )
  6 个评论
显示 4更早的评论
Tino
Tino 2019-5-1
编辑：Tino 2019-5-1
sorry the right figure is the one below. sorry for giving wrong computation
Can you help me with the short code to gives the following answers for h = any number for instance
when h = 1
1
4
5
7
when h = 2
1
7
7
3
when h = 3
1
10
1
13
thanks in advance
Guillaume
Guillaume 2019-5-1
In your question, you told us than when h = 2, a = [1 7 3 11] (for P = [1, 4, 5, 7]) and this is the answer that my code produces. I have no idea how you get your new answer. It doesn't match the formula you've posted.

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