how to replace elements in top third, middle third, and bottom third of matix

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Marlon Izaguirre
Marlon Izaguirre 2019-5-1
评论： Ammar 2023-9-27
This question is soft-locked: new answers that are equivalent to already posted answers may be deleted without prior notice.
My task is the following:
Write a function called trio that takes two positive integer inputs n and m. The function returns a 3n-by-m matrix called T. The top third of T (an n by m submatrix) is all 1s, the middle third is all 2-s while the bottom third is all 3-s. See example below:
M = trio(2,4)
M =
1 1 1 1
1 1 1 1
2 2 2 2
2 2 2 2
3 3 3 3
3 3 3 3
This is the code that I wrote, but it only works for T = trio (4,3). I want my code to work for any input of n,m.
function T = trio (n, m)
T = randi (10, (3 * n) , m);
T ( 1:n , :) = 1;
T ( (n+1):(end-(n-1)) , :) = 2;
T ( (n+3):end, :) = 3;
end
How is it possible to call out only top third, middle third, and bottom third of any matrix?
Thank you in advance.
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Rik
Rik 2020-8-17
编辑：Rik 2020-8-18
I'm going to delete duplicate answers. I will consider the list below as the list of solutions. From the current answer section I will only leave the top one for each of these:
  1. all answer with general advice about how to solve the question
  2. answers with more than 1 vote
  3. allocating the full size array with ones or zeros and indexing into it, writing the correct values
  4. allocating the full size array with a non-standard function (like randi) and indexing into it, writing the correct values
  5. 3 and 4, but for the three parts separately, requiring concatenation
  6. kron (posted in a comment)
  7. repmat combined with implicit expansion
If new valid solutions are posted I will of course leave those as well, although I think the non-esoteric solutions may be exhausted.

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采纳的回答

James Tursa
James Tursa 2019-5-1
编辑：James Tursa 2019-5-1
Your row indexing is wrong.
The first n rows are 1:n which you have correct.
The second n rows indexing is n more that the first set, so simply add n: n + (1:n)
The third n rows indexing is n more than the second set, which I will let you figure out (it's pretty simple)
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Ammar
Ammar 2023-9-27
function T = trio (n, m)
T =randi (10, (3 * n) , m)
T ( 1:n , :) = 1
T ( (n+1):2*n , :) = 2
T ( (2*n+1):end, :) = 3
end

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更多回答（6 个）

AYUSH GURTU
AYUSH GURTU 2019-5-28
function T = trio (n, m)
T = randi (10, (3 * n) , m);
T (1:n,:) = 1;
T ((n+(1:n)),:) = 2;
T (n+(n+(1:n)):end,:) = 3;
end
PRAKASH ANAND
PRAKASH ANAND 2019-11-8
% That's my trio code.
%From India.
function T=trio(n,m)
x=ones(n,m);
y=2*x;
z=3*x;
T=[x;y;z];
end
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OUSSAMA El GABBARI
OUSSAMA El GABBARI 2022-1-19
that function you made I see it's very restricted.. I wonder if it'd work for matrices of larger dimensions !

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evan muas
evan muas 2019-12-2
function T=trio(n,m)
T=[ones(n,m);2*ones(n,m);3*ones(n,m)]
end
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Juvraj Singh Sandhu
编辑：Juvraj Singh Sandhu 2020-10-4
this will work for all inputs
function T= trio(n,m);
T1= ones(n,m);
T2= 2*ones(n,m);
T3= 3*ones(n,m);
T= [T1;T2;T3];
  2 个评论
Stephen23
Stephen23 2023-9-8
"but i dont think function will return 3n by m matrix."
Please show any positive integer values of m & n for which this function does not return a 3n by m matrix.

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mayank ghugretkar
function T=trio(n,m)
T(3*n,m)=3; % or you can use random no. generation...but since we are assigning alues anyway , this vl work fine !
T(1:n,:)=1;
T((n+1):2*n,:)=2;
T((2*n+1):3*n,:)=3;
end
hope this'll help, welcome !
Doga Savas
Doga Savas 2019-8-22
function d = trio(n,m)
a = randi(1,n,m);
b = 2 + rand(n,m)*0;
c = 3 + rand(n,m)*0;
d = [a;b;c];
end
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Rik
Rik 2023-9-8
Ran in:
trio_even_less_baloney = @(n,m) repelem((1:3).',n,m);
n=2;m=4;
trio_even_less_baloney(n,m)
ans = 6×4
1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3
Although your point is absolutely valid.
DGM
DGM 2023-9-8
Yeah, maybe I should've called it trio_reduced_baloney()
I figured repelem() was already officially exhausted. Reshaping/permuting might not be minimal, but it was a reasonable basic option that was still fair game.

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