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Extract part of a filename from a directory list

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Tom Wright
Tom Wright 2012-8-14
评论： Sogand Karbalaieali 2017-4-12
Hi, Can anyone please show me a 'nice' way to achieve what I what, preferably without looping.
I have a folder containing multiple files with similar format names 'XXX_YYY_010203.txt'. The numeric part is a timestamp, I would like to extract the timestamps into an array.
Currently my code looks like this:
filelist=dir(folder);
x=regexp({filelist(:).name},'_','split')
x=cellfun(@(x) regexp(x(3),'\.','split'),x)
x=cellfun(@(x) x(1),x)
Which works, but isn't exactly readable.

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采纳的回答

Oleg Komarov
Oleg Komarov 2012-8-14
I suppose that your filenames always have the date as ddmmyy and it's always at then end:
x = {'XXX_YYY_010203.txt'
'XXX_YYY_020203.txt'};
x = cellfun(@(in) in(end-9:end-4),x,'un',0)
  2 个评论
Tom Wright
Tom Wright 2012-8-14
Thanks
x = cellfun(@(in) in(end-9:end-4),{filelist(:).name},'un',0)
Sogand Karbalaieali
Sogand Karbalaieali 2017-4-12
Thank you. Also, if all file names do not have the same patterns, those with different name pattern shall be excluded to avoid error in the code.

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