Count size of groups of 1's

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David AR
David AR 2019-5-3
回答： Pablo Rozier-Delgado 2023-7-13
Hi all, this is my first question on the forum.
I have a vector called gpos that have 1's where I have a NaN value (gpos = isnan(data);)
For example
gpos = [1 1 1 0 0 1 1 0 1 1]'
I'd like to count the size of groups of 1's, like my expected result. How do I accomplish that? Thanks in advance.
result = [3 2 2]' % ignoring data that is zero

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采纳的回答

Erivelton Gualter
Here is a way you can perform this:
gpos = [1 1 1 0 0 1 1 0 1 1]';
[I, ~] = find(gpos == 1);
k = 0;
result = [];
for i=2:length(I)
if (I(i)-I(i-1)) ~= 1
result = [result; k+1];
k = 0;
else
k = k + 1;
end
end
result = [result; k+1];
disp(result);
But definetly, you might write something simpler .
  1 个评论
Matt J
Matt J 2021-3-29
David AR's comment moved here:
Thank you. The code works flawlessly. Best regards.

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更多回答（1 个）

Pablo Rozier-Delgado
Ran in:
Another way, without for loop:
gpos = [1 1 1 0 0 1 1 0 1 1]'; % Detected NaNs
indGroups = bwlabel(gpos) + 1; % Label groups of ones and make it positive integers
result = accumarray(indGroups,gpos); % sum of each groups
result(result == 0) = [] % delete the 0 group
result = 3×1
3 2 2

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