How can I create a cell array whose elements reflect a length based on a given input vector?

Question

Dwight Schrute III 2019-5-3

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/460127-how-can-i-create-a-cell-array-whose-elements-reflect-a-length-based-on-a-given-input-vector

评论： Dwight Schrute III 2019-5-4

For example, I want to repeat the character 'b' a specified number of times based on a vector; let's say the vector is [3 2 4]. My desired output would be a 1x3 cell array with elements:

{'bbb'} {'bb'} {'bbbb'}

Ideally, I'd like to implement this without a loop. I'm sure there's some nifty Matlab function that accomplishes this, but I haven't been able to find it. repmat and repelem don't appear to be relevant for this particular application (unless I'm using them incorrectly).

Thank you.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

KALYAN ACHARJYA 2019-5-4

在 MATLAB Online 中打开

Members, how can avoid this for loop?

in=[3 2 4];
result={};
for i=1:length(in)
    result{i}=repmat('b',1,in(i));
end 

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Stephen23 2019-5-4

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/460127-how-can-i-create-a-cell-array-whose-elements-reflect-a-length-based-on-a-given-input-vector#answer_373588

在 MATLAB Online 中打开

In one line:

>> V = [3,2,4];
>> S = 'b';
>> C = mat2cell(repmat(S,1,sum(V)),1,V);
>> C{:}
ans = bbb
ans = bb
ans = bbbb

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Dwight Schrute III 2019-5-4

Nimble utilization of mat2cell functionality. This works perfectly; I wish I had thought of it. Thanks for your answer, Stephen.

请先登录，再进行评论。

How can I create a cell array whose elements reflect a length based on a given input vector?

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

采纳的回答

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

更多回答（0 个）

另请参阅

类别

标签

Community Treasure Hunt

How can I create a cell array whose elements reflect a length based on a given input vector?

1 个评论 显示 -1更早的评论隐藏 -1更早的评论

采纳的回答

1 个评论 显示 -1更早的评论隐藏 -1更早的评论

更多回答（0 个）

另请参阅

类别

标签

Community Treasure Hunt

WeChat

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

1 个评论
显示 -1更早的评论隐藏 -1更早的评论