matlab negative and positive infinity problem
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hi there,
I am quite confused about how matlab deals with inf and -inf. Here is the problem I confronted
x0p = 0;
b = 0.0050;
y0p =0;
(x0p-b)/y0p
ans =
Inf
But it should be -inf. I changed the value of b but still got the same answer. I tried using numbers directly and it seems correct as shown below. I don't know the mechanism behind it. So I hope someone could help me figure it out.
-1/0
ans =
-Inf
Cheers,
Jianan
3 个评论
madhan ravi
2019-5-4
编辑：madhan ravi
2019-5-4
sprintf('%.32f',x0p) % what does it result to?
I get -Inf btw.
Walter Roberson
2019-5-4
-Inf is what shows up for me in R2019a. Which version are you using, on which operating system?
I suggest you use num2hex(x0p) and y0p to verify that they are true zeros. Also, store the result in a variable and use num2hex() on it. -inf is fff followed by all 0, and +inf is 7ff followed by all 0.
Jianan He
2019-5-4
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