use a Loop to repeat an equation using the previous answer as the new variable.

2019 5 4
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更新时间：2019 5 4
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I want to write a loop to do the below all the way up to p340....I do not want to change the name of the variable each time but instead would like all variables in one array. I have been searching and trying to figure this out for hours. I've written so many different forms of a for loop I don't know what to include here.
xt = 100:440
p1 = 99977
p2 = p1./(exp((50)./(29.3.*((xt)))))
p3 = p2./(exp((50)./(29.3.*((xt)))))
p4 = p3./(exp((50)./(29.3.*((xt)))))
....etc

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I would like to close my other question but don't know how. I'd like for this question to stay open.
madhan ravi
madhan ravi 2019-5-4
So anyhow you have wasted one of the answerers effort.
I would have closed the question sooner if i knew how...maybe the site should make it easier to close a question and efforst would not have been wasted.

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KALYAN ACHARJYA
KALYAN ACHARJYA 2019-5-4
编辑：KALYAN ACHARJYA 2019-5-4

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xt=100:440;
p={};
p{1}=99977;
for i=2:340;
p_iter=p{i-1};
deno=exp(50./(29.3*(xt)));
p{i}=p_iter./deno;
end

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Ok...this give me the correct values...however it gives it to me in a 1X340 cell where each cell contains a 1X340 array...the first value of the array in that cell is the correct value for that iteration...but I just need one array not a bunch of cells filled with a bunch of arrays.
Ok so one small change and it's solved...thanks!
xt=100:440;
p={};
p{1}=99977;
for i=2:340;
p_iter=p{i-1};
deno=exp(50./(29.3*(xt(i))));
p{i}=p_iter./deno;
end
Stephen23
Stephen23 2019-5-4
编辑：Stephen23 2019-5-4
".the first value of the array in that cell is the correct value for that iteration.."
That is quite interesting, because the first values of each vector corresponds to the first value of the xt vector. So effectively you want to ignore all of the other xt values. Is this correct?
EDIT: you have now accepted KALYAN ACHARJYA's complex answer, which according to your own comment does not do what you want. You wrote: ".the first value of the array in that cell is the correct value for that iteration" and now you have shown in your own comment (by the addition of xt(i) indexing) that what you described is not what you want at all.
Also note that KALYAN ACHARJYA does not provide a numeric vector, as you requested.
Simpler answer:
https://www.mathworks.com/matlabcentral/answers/460171-variable-changes-to-previously-calculated-value-each-iteration#answer_373592

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