How do I plot the bode plot of the transfer function with exp(sT)?

4 次查看（过去 30 天）
yklu008
yklu008 2019-5-6
回答： Raj 2019-5-6
The transfer function is show as following, where T=10e-9.
How could I get the bodeplot from this function?
59538682_243684739829449_8500004122919960576_n.jpg
  1 个评论
David Wilson
David Wilson 2019-5-6
Since you have the time delay element in the denominator, your don't have a polynomial transfer function anymore, so you will need to approximate it using pade.
You also might want to check that it is exp(-Ts), not the acausal version you have written above.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Raj
Raj 2019-5-6
You can rearrange the equation as (e^-sT)(s+10)/s(1-(e^-sT))
Then your code should look something like this:
s = tf('s');
T=10e-9;
f = exp(-T*s);
sys=(f*(s+10))/(s*(1-f))
bode(sys)

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Time-Domain Analysis 的更多信息

标签

产品


版本

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by