dispay error in command window

I have a variable which contains complex values (FFT result). As you can see in the above figure, the second imaginary value in this variable is negative. When i load the second value to a variable 'aa' as a transpose, it retains the negative component. But when i load as it is, to the variable 'bb', it doesnt show as a negative component. Why is that ? this is perplexing.

 采纳的回答

Walter Roberson
Walter Roberson 2019-5-9

0 个投票

The ' operator is not the transpose operator: it is the conjugate transpose operator. The transpose operator is .'

3 个评论

Ahh. In which case, if I use
(signIm(freqdata1(1,2)))
why is the resultant value not a -1 ? . Any ideas ?
I do not appear to find any function named signlm?
Ahh. never mind. i had taken the complex tranpose earlier of freqdata as it is. My mistake. Thank you for your help.

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by