If i generate the complex gaussian in this method,are the sub-matrix all complex gaussian?

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yang-En Hsiao
yang-En Hsiao 2019-5-10
The main goal is to create 4 complex gaussian matrix ,h1~h4,each gaussian matrix is 4 by 1 matrix,and the direct method is
h1=sqrt(1/2)*(randn(4,1)+1i*randn(4*1));
h2=sqrt(1/2)*(randn(4,1)+1i*randn(4*1));
h3=sqrt(1/2)*(randn(4,1)+1i*randn(4*1));
h4=sqrt(1/2)*(randn(4,1)+1i*randn(4*1));
But if i want to use this method
H=sqrt(1/2)*(randn(4,4)+1i*randn(4*4));
for n=1:4
h{n}=H(1:4,n)
end
We know that h{1},h{2},h{3},and h{4} are all 4 by 1 matrix,but are they all complex gaussian ?If not,is there any way to generate lots of complex gaussain,except the first method i provide?

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