Saving all output of for loop
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for i=1:1500
X1=J(i)-sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y1=I(i)-A(i)*(J(i)-X1)
X2=J(i)+sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y2=I(i)+A(i)*(X2-J(i))
end
coord=[X1(:),Y1(:),X2(:),Y2(:)]
%coord
writematrix(coord,'Coord_15.csv')
I am trying to save the coordinates (X1, X2, Y1,Y2) from a for loop as shown in the code above. All inputs (I, J, A, D) are columns vectors , but i only the last iteration is saved. I will appreciate any help.
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采纳的回答
Sulaymon Eshkabilov
2019-5-12
Hi,
Simply add (i) after your output variables, viz. X1, Y1, X2, Y2:
for i=1:1500
X1(i)=J(i)-sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y1(i)=I(i)-A(i)*(J(i)-X1)
X2(i)=J(i)+sqrt((D(i)^2)/((sqrt(A(i))+1)))
Y2(i)=I(i)+A(i)*(X2-J(i))
end
coord=[X1(:),Y1(:),X2(:),Y2(:)]
%coord
writematrix(coord,'Coord_15.csv')
Good luck
4 个评论
madhan ravi
2019-5-16
编辑:madhan ravi
2019-5-16
Then why did you accept the answer if it doesn’t solve the problem??
Sulaymon Eshkabilov
2019-5-16
Before commenting any point verify what you have stated. That is the correct answer. Vectorization is another solution.
更多回答(1 个)
madhan ravi
2019-5-12
编辑:madhan ravi
2019-5-16
You don't need a loop , this is straight forward just vectorize your code:
Note: The other answer doesn‘t show the importance of preallocation.
X1=J-sqrt((D.^2)./((sqrt(A)+1)));
Y1=I-A.*(J-X1);
X2=J+sqrt((D.^2)./((sqrt(A)+1)));
Y2=I+A.*(X2-J);
coord=[X1(:),Y1(:),X2(:),Y2(:)];
writematrix(coord,'Coord_15.csv')
2 个评论
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