How can I estimate the average for each one of the intervals in an x axis?
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Hi
I need a method to split my x axis into intervals and estimate the average for each one of the intervals. The plots are polynomial curves, if that helps.
Any suggestion?
Thank you
2 个评论
Jan
2019-5-17
The question is not clear yet: It does not make sense to "split the x axis". But if you have two vectors, one containing the x and the other the y values of a curve, you can calculate a blockwise average. So please post, what your inputs are.
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Adam Danz
2019-5-19
编辑:Adam Danz
2019-5-20
This is relatively straight forward with histcounts() and splitapply().
% Create fake data
x = randi(1000,1,1000); %doesn't have to be sorted
y = rand(size(x));
% Define the edges of your x data
% There's lots of ways to do this - this is just 1 example.
binWidth = 100; %how wide is each bin?
edges = min(x) : binWidth : max(x);
% determine which bin each x element is in
[~, ~, hbin] = histcounts(x,[edges,inf]);
% Get mean of y within each bin
% Here I ignore NaN values, too.
binMean = splitapply(@(x)mean(x,'omitna'),y,hbin);
To interpret the results, binMean(n) is the mean for all y values where x is greater or equal to edges(n) and less than edges(n+1).
To plot the data, the bins, and display the average values per bin above the axis:
figure
plot(x,y,'b.')
hold on
plot([edges;edges],[0,1],'k')
text(edges+binWidth/2, ones(size(edges)), strsplit(num2str(binMean,.1)), ...
'VerticalAlignment', 'Bottom', 'HorizontalAlignment', 'Center')
% * binMean must be a row vector
13 个评论
Adam Danz
2019-5-20
编辑:Adam Danz
2019-5-20
Glad I could help.
The 2nd input to text() indicates where along the y axis your labels should go. In my example I simply used y=1 for all labels because my data didn't span beyond 1. You could just do this
ylim([-0.5, 2])
text(edges+binWidth/2, ones(size(edges))*max(ylim()), ......
also, see the "rotation" text property. It might look better to rotate the labels by 90 deg.
Also, to draw the lines across your entire axis,
plot([edges;edges],[min(ylim()), max(ylim())],'k')
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