Problem with array filling

11 次查看(过去 30 天)
Hi,
I need to do this:
for i=0.1:0.1:360
j(i*10)=2;
end
but I obtain this error message:
??? Attempted to access j(3); index must be a positive integer or
logical.
Could you help me?
Thanks in advance
Thomas

采纳的回答

Image Analyst
Image Analyst 2012-8-17
Besides the others all saying to cast your index to integer like this:
for k = 0.1 : 0.1 : 360
jArray1(int32(k * 10)) = int32(2);
end
I also want to say that it's usually recommended not to use i and j (though you can) as variable names since they also are the imaginary variable. Hence my new names in the corrected code above.
Also, there are some other ways that are more probably efficient and "MATLAB-ish" to do what you did, such as the methods below:
jArray2 = 2 * ones(1, 3600, 'int32');
jArray3(1 : 3600) = int32(2);

更多回答(4 个)

Oleg Komarov
Oleg Komarov 2012-8-17
编辑:Oleg Komarov 2012-8-17

Matt Fig
Matt Fig 2012-8-17
编辑:Matt Fig 2012-8-17
The reason you get this error is because of floating point arithmetic.
Look closely:
isequal((0.1:0.1:1)*10,1:10) % NO!
Here is the closer look:
x = (0.1:0.1:1)*10;
x==(1:10) % Notice the third return is a zero, here's why:
fprintf('%.16f\n%.16f\n',x(3),3) % Print out and compare...

Azzi Abdelmalek
Azzi Abdelmalek 2012-8-17
编辑:Azzi Abdelmalek 2012-8-17
in matlab index must be a real strict positiv integer
it does'nt accept x(0) or x(-1)
h=zeros(360*10/0.1,1)
for j=0.1:0.1:360
ind=int16(j*10) % convert to integer, for biger number, u can use int32, int64
h(ind)=2;
end

thomas82
thomas82 2012-8-18
Thank you for your answers, now I understood and resolved! Thomas

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by