Info
此问题已关闭。 请重新打开它进行编辑或回答。
How do I set up a particular function
1 次查看(过去 30 天)
显示 更早的评论
Dear all,
I have a function
f=@(x) umax(x,u, t);
The problem is that x changes at each value of t=1,...,T; that is,
LL= function umax(x,u, t);
if t==1
u=[x; u(2:T) ];
elseif t==T
u=[u(1:T-1);x ];
else
u=[u(1:t-1);x;u(t+1:T) ];
end
LL='some function of the sum of u which I skip now'
end
Is the above code correct or the code below?
f=@(x) umax(x,u, t);
LL= function umax(x,u, t);
u(t)=x
LL='some function of the sum of u which I skip now'
end
LL produces a scalar.
Thanks a lot
5 个评论
Walter Roberson
2019-5-16
The first one requires that a function named T has been defined that returns a scalar and that t is a nonnegative integer scalar. 0 is ok for t for the first one.
The second one is more efficient but requires that t be positive integer. 0 is not possible there. A vector or array of t is possible as long as x is scalar or the same number of entries.
回答(0 个)
此问题已关闭。
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!