How do I set up a particular function

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ektor 2019-5-15

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Dear all,

I have a function

f=@(x) umax(x,u, t);

The problem is that x changes at each value of t=1,...,T; that is,

 
LL= function umax(x,u, t);
     if t==1
     u=[x; u(2:T) ];
elseif t==T
 u=[u(1:T-1);x ];   
else
 u=[u(1:t-1);x;u(t+1:T) ]; 
     end
     
     
LL='some function of the sum of u which I skip now'
end
      

Is the above code correct or the code below?

  f=@(x) umax(x,u, t);
 
LL= function umax(x,u, t);
  u(t)=x
        
LL='some function of the sum of u which I skip now'
end

LL produces a scalar.

Thanks a lot

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Walter Roberson 2019-5-16

The first one requires that a function named T has been defined that returns a scalar and that t is a nonnegative integer scalar. 0 is ok for t for the first one.

The second one is more efficient but requires that t be positive integer. 0 is not possible there. A vector or array of t is possible as long as x is scalar or the same number of entries.

ektor 2019-5-16