Attempted to access i(3); index out of bounds because numel(i)=2

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Mahmoud Hassan 2019-5-17

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/462757-attempted-to-access-i-3-index-out-of-bounds-because-numel-i-2

回答： Walter Roberson 2019-5-18

在 MATLAB Online 中打开

i am getting this error

"Attempted to access i(3); index out of bounds because numel(i)=2 ".

exactly in the line 289 below:

Table=[3*pi/4 2*pi/3 pi/2 pi/3 pi/4 
       5*pi/6 0 0 0 pi/6
       pi 0 0 0 0
      -5*pi/6 0 0 0 -pi/6
      -3*pi/4 -2*pi/3 -pi/2 -pi/3 -pi/4];
for ind=1:length(CentroidBifX)
    Klocal=K(CentroidBifY(ind)-2:CentroidBifY(ind)+2,CentroidBifX(ind)-2:CentroidBifX(ind)+2);
    Klocal2=K(CentroidBifY(ind)-1:CentroidBifY(ind)+1,CentroidBifX(ind)-1:CentroidBifX(ind)+1);
    Klocal(2:end-1,2:end-1)=0;
    Klocal2(2:end-1,2:end-1)=0;
    [i,j]=find(Klocal);
    [i2,j2]=find(Klocal2);
    length(i)
    if length(i)> 3
         for k=1:3
            OrientationBif(ind,k)=Table(i2(k),j2(k));
            dxBif(ind,k)=sin(OrientationBif(ind,k))*3;
            dyBif(ind,k)=cos(OrientationBif(ind,k))*3;
        end
    else
        for k=1:3
    OrientationBif(ind,k)=Table(i(k),j(k));         "line of error"    
            dxBif(ind,k)=sin(OrientationBif(ind,k))*5;
            dyBif(ind,k)=cos(OrientationBif(ind,k))*5;
        end
    end
end

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Mahmoud Hassan 2019-5-18

you would understand the whole 289 lines if i put them all ?! and for your question i am just new to matlab and trying to understand some errors i have

madhan ravi 2019-5-18

Sulaymon Eshkabilov's comment mistakenly posted as answer:

Hi,

Undefined function or variable 'CentroidBifX'? What is your set variable 'CentroidBifX'?

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Answer 1

Walter Roberson 2019-5-18

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/462757-attempted-to-access-i-3-index-out-of-bounds-because-numel-i-2#answer_375591

在 MATLAB Online 中打开

if length(i)> 3

so if is more than 3 long you execute this code

         for k=1:3
            OrientationBif(ind,k)=Table(i2(k),j2(k));
            dxBif(ind,k)=sin(OrientationBif(ind,k))*3;
            dyBif(ind,k)=cos(OrientationBif(ind,k))*3;
        end
    else

and if you got here, then i is empty, or i is length 1, or i is length 2, or i is length 3.

        for k=1:3
    OrientationBif(ind,k)=Table(i(k),j(k));         "line of error"   

that is going to fail if i is empty, or length 1, or length 2. It is only going to work if i is length 3.

Based upon your error message, i is length 2. We, as outside observers, have no reason to expect that it will be any particular length.

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Attempted to access i(3); index out of bounds because numel(i)=2

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Attempted to access i(3); index out of bounds because numel(i)=2

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