Adding Zeroes and Ones into a Vector
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I have a 1x300 vector and would like to make it into a 1x400 vector by inserting a 0 after every third element, a 0 after every sixth element and a 1 after the ninth element and then after the twelfth element insert a 0 and repeat the pattern.
So for example if I have
0 0 1 0 1 0 1 0 0
this would become
0 0 1 0 0 1 0 0 1 0 0 1
and so on.
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dpb
2019-5-19
编辑:dpb
2019-5-22
>> v=reshape([reshape(v,[],3),[0 0 1].'].',1,[])
v =
0 0 1 0 0 1 0 0 1 0 0 1
>>
To generalize, repmat the augmentation vector as many times as needed.
>> v=reshape([reshape(v,[],3),repmat([0 0 1].',numel(v)/9,1)].',1,[])
v =
0 0 1 0 0 1 0 0 1 0 0 1
>>
ADDENDUM: To make the generalizaton more clear perhaps...
lenStr=3; % length prior to insertion point
vaug=[0 0 1].'; % the augmenting vector
lenAug=numel(vaug); % length of augmentation vector
v=reshape([reshape(v,[],lenStr),repmat(vaug,numel(v)/(lenStr*lenAug),1)].',1,[])
6 个评论
dpb
2019-5-21
Same logic works with the augmentation vector being only 1 element, too:
reshape([reshape(v,[],3) ones(108/3,1)].',1,[])
You just have to compute the repeat factor correctly dependent upon the length being added--how many rows does it add each time?
The above with the hardcoded '9' was specific for the original question of 3.
更多回答(1 个)
Jos (10584)
2019-5-21
Inserting elements at specific locations is not trivial. Years ago I wrote a function INSERTROWS that does this
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