For with a 0.1 step

Question

Marc Sabaté 2019-5-20

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/463132-for-with-a-0-1-step

回答： Star Strider 2019-5-20

Sorry for this post because I'm sure that is a really simple thing. I'm trying to compute a function between 1 to 10 with a step of 0.1 with a for loop. I wrote it like this:

for i=1:0.1:10;
    theta=0;
    betha=1/(1/(i+0.08*theta)-0.035/(1+theta^3));
    Cp(i)=C1*(C2/betha-C3*betha*theta-C4*theta-C5)*exp(-C6/betha);
end

Matlab gives me the error: Array indices must be positive integers or logical values.

I understant that the problem here is how the index is the defined but I don't know how to solve it

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Alexander Guth 2019-5-20

在 MATLAB Online 中打开

Just let i be an an integer index and multiply it with your step size inside the loop like this:

i * 0.1

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Star Strider 2019-5-20

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/463132-for-with-a-0-1-step#answer_375886

在 MATLAB Online 中打开

Indices must be integers greater than 0, or logicals.

Try this:

i=1:0.1:10;
for k = 1:numel(i)
    theta=0;
    betha=1/(1/(i(k)+0.08*theta)-0.035/(1+theta^3));
    Cp(k)=C1*(C2/betha-C3*betha*theta-C4*theta-C5)*exp(-C6/betha);
end