combining different csv files from a folder into one matrix
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Hello, I have 800 files with 1554rows and 2columns so (1554x2) , that I'd like to read from a folder and then combine them into a large matrix of 1554x801. The first column is common to each file, and so I'd like to set only the first column in the final matrix as the same column of all the files, and then the subsequent columns as the second column of each of the 800 files. I hope this makes sense.
Example:
A.csv=[1 2; 4 5] and B.csv=[1 8 ;4 7], C.csv=[1 6;4 10]
I'd like to combine these into
Combined=[1 2 8 6; 4 5 7 10]
Would anyone possibly have a code for this? I'm new to Matlab and have tried a number of codes that merge files. but they stack them horizontally so I get
[1 2;4 5;1 8;4 7;1 6;4 10].
Thank you!
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采纳的回答
Stephen23
2019-5-22
编辑:Stephen23
2019-5-22
"Is theremaybe a way to list the filenames in the same order, then add them afterwards as the top row to the table?"
O = {'ReadVariableNames',false};
D = '.'; % path to the directory where the files are saved.
S = dir(fullfile(D,'*.csv'));
for k = 1:numel(S)
U = readtable(fullfile(D,S(k).name),O{:});
[~,N] = fileparts(S(k).name);
U.Properties.VariableNames = {'time',N};
if k==1
T = U;
else
T = join(T,U);
end
end
Giving (the test files are attached to this answer):
>> T
T =
time A B C
____ _ _ __
1 2 8 6
4 5 7 10
>> T.B
ans =
8
7
更多回答(1 个)
KSSV
2019-5-22
csvfiles = dir('*.csv') ;
iwant = zeros(1554,801) ;
for i = 1:length(csvfiles)
data = csvread(csvfiles(i).name) ;
if i == 1
iwant(:,1:2) = data ;
else
iwant(:,i+1) = data(:,2) ;
end
end
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