Joining every eight columns in a matrix
显示 更早的评论
Hi there! Right now I have a (large by 46) double Matrix. An example is shown below:
[1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8; ...]
I'd like to update it so that it is:
['12345678' '12345678'; ...]
I know that it should be something with character joining but I'm just not quite sure of what the exact steps are.
Thanks for your help!
采纳的回答
Although it might visually be joining characters, that is not necessarily what you need. The code below should be one of the faster methods, although it breaks when your elements are larger than 9 or non-integer. The nice thing about this system is that you can replace fun with any function (or handle to a function) so you can make sure it does the conversion in a way you want.
bigData=[1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8; ...
1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8; ...
1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8];
a=mat2cell(bigData, ones(size(bigData,1),1), [8 8]);
fun=@(x) polyval(x,10);
b=cellfun(fun,a);
If you do want to convert to characters, do the join and convert back to double:
fun=@(x) str2double(cell2mat(cellfun(@num2str,num2cell(x),'uni',0)));
Although that function will also break for non-integer values.
2 个评论
Nick DeMarchis
2019-5-22
Rik
2019-5-22
In that case it appears your data is not actually a double array, but a char array. That makes it a bit easier, as we can just remove the spaces and optionally convert the result to a double array.
bigData=['1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8'; ...
'1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8'; ...
'1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8'];
%remove all spaces
a1=strrep(bigdata,' ','');
%divide lines in two blocks of 8 (using a cell array)
a2=mat2cell(a, ones(size(a,1),1), [8 8]);
%convert char to double
b=cellfun(@str2double,a2);
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