How can I find a vector in a matrix without using cycles?
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Good afternoon. The reason for my message is to ask for help with this problem. Let's say I have a matrix "called A" with 2 columns and -n- number of rows, and I need to look for a vector "B" (which is 1 row and 2 columns) within all the rows that make up "A". You must find the vector in a way that recognizes in a sense or in the opposite sense, then I show an example to better understand what I say.
A =
1 2
3 4
5 3
3 1
6 4
4 2
B=
4 6 -------------------> The vector B can also be inverted (6 4).
The result I expect to be told in which row is the vector "B" inside the matrix "A". for the example above I would expect the answer to be row 5
Thank you very much for your help.
采纳的回答
Star Strider
2019-5-22
Try this:
A = [1 2
3 4
5 3
3 1
6 4
4 2];
B = [4 6];
Lidx = ismember(sort(A,2),sort(B,2),'rows')
rowNumber = find(Lidx)
producing:
Lidx =
6×1 logical array
0
0
0
0
1
0
rowNumber =
5
4 个评论
Pedro Guevara
2019-5-22
Star Strider
2019-5-22
As always, my pleasure.
Pedro Guevara
2019-5-22
Star Strider
2019-5-23
Again, as always, my pleasure.
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