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How to store matrix whose dimension is changing in each iteration ?

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Manoj Kumar
Manoj Kumar 2019-5-24
编辑： KALYAN ACHARJYA 2019-5-28
hello all
How to store matrix whose dimension is changing in each iteration?
can anyone expalin with example?

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回答（2 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2019-5-24
编辑：KALYAN ACHARJYA 2019-5-24
Cell array
result=cell(1,iter);
for i=1:iter
%say matrix1 have changes the dimention in each iteration
% do operation, say matrix1 is the result in this iteraion.
result{i}=matrix1
end
Exampele:
>> A=rand(2,4)
A =
0.9324 0.2304 0.8681 0.9226
0.2963 0.1660 0.2219 0.9020
>> B=magic(3)
B =
8 1 6
3 5 7
4 9 2
>> result={A,B}
result =
1×2 cell array
{2×4 double} {3×3 double}
>>
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KALYAN ACHARJYA
KALYAN ACHARJYA 2019-5-28
编辑：KALYAN ACHARJYA 2019-5-28
Where is the issue, can you share?
As per your question>>
How to store matrix whose dimension is changing in each iteration ?
Best way Celll Array (Alreadt shown the example too)
>> A=rand(2,4)
A =
0.9324 0.2304 0.8681 0.9226
0.2963 0.1660 0.2219 0.9020
>> B=magic(3)
B =
8 1 6
3 5 7
4 9 2
>> result={A,B}
result =
1×2 cell array
{2×4 double} {3×3 double}
>>
Here we have saved the two matrix having sizes 2x4 and 3x3 in result cell array.

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Raj
Raj 2019-5-24
编辑：Raj 2019-5-24
Use cell array
for i = 1:10
A = rand(i,i) % A size is changing with every iteration
B{i} = A; % Store A as cell
end
Required_matrix=cell2mat(B(1,10)) % Suppose I want to extract the 10th iteration matrix
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Manoj Kumar
Manoj Kumar 2019-5-28
its working direcctly, but If we get A return from functioion then how wil to strore it.
e.g. [A, B] = function1(arg1, arg2).
Actually I trying to fix this issue.

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