How to calculate the euclidean distance in matlab?

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Avinash Bhatt
Avinash Bhatt 2019-5-26
编辑： KALYAN ACHARJYA 2019-5-26
I have coordinates as
pix_cor=[2 1;2 2; 2 3]
I want to calculate the eucledian distance between
1) (2,1) and (2,1);
2) (2,1) and (2 2);
3) (2,1) and (2,3);
Simarlarily
4) (2,2) and (2,1);
5) (2,2) and (2 2);
6) (2,2) and (2,3);
and
7) (2,3) and (2,1);
8) (2,3) and (2 2);
9) (2,3) and (2,3);
The formulae is (x2-x1)^2+(y2-Y1)^2
The result will be h=[0 1 1;1 0 1;4 1 0]
Please help me achieving this in matlab

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采纳的回答

KALYAN ACHARJYA
KALYAN ACHARJYA 2019-5-26
编辑：KALYAN ACHARJYA 2019-5-26
%#Edited
x=[2,1];
y=[2,1];
D=sqrt((y(1)-x(1))^2+(y(2)-x(2))^2);
Result:
D =
0
So on.......% do the same for others

更多回答（1 个）

John D'Errico
John D'Errico 2019-5-26
Actually, that is simply NOT the formula for Euclidean distance. You need to take the square root to get the distance. So, you showed the formula for the square of the distance.
pix_cor=[2 1;2 2; 2 3];
x = pix_cor(:,1);
y = pix_cor(:,2);
Now, what does MATLAB do if you form differences like these?
x - x'
and
y - y'
TRY IT! Learn to use MATLAB!
So the trick is to square those matrices, then add the results, then take the square root. Like this:
dist_E = sqrt((x - x').^2 + (y - y').^2)
dist_E =
0 1 2
1 0 1
2 1 0
As I said, the Euclidean distance NEEDS a square root though. It you don't believe me, then do some reading here:
https://en.wikipedia.org/wiki/Euclidean_distance
The above line of code does require MATLAB release R2016b. With an older release, you would use bsxfun.
dist_E = sqrt(bsxfun(@minus,x,x').^2 + bsxfun(@minus,y,y').^2);

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