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Convert matlab zeros function to Python equivalent

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Prb
Prb 2019-5-28
评论： Murugan C 2019-5-29
Hi Could you pleas elet me know what would be a similar conversion of matlab zeros to np.zeros for datatype. I am getting an error while doing this.
Matlab code:
Shifts = zeros(length(Filters)-1,1,'int16');
Python code:
Shifts = np.zeros(len(Filters)-1,1,dtype = np.int16)
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Prb
Prb 2019-5-29
It took only the negative dimensions and which is not allowed.
Murugan C
Murugan C 2019-5-29
What is size of the Filters. If lenght of "Filters" is empty or zeros, then only you will get negative dimensitons.
>>> import numpy
>>> Filters = [ ]
>>> Shifts = numpy.zeros(len(Filters)-1,dtype = numpy.int16)
Traceback (most recent call last):
File "<pyshell#20>", line 1, in <module>
Shifts = numpy.zeros(len(Filters)-1,dtype = numpy.int16)
ValueError: negative dimensions are not allowed
>>>
%%
>>> Filters = [5, 6, 4, 5,6]
>>> Shifts = numpy.zeros(len(Filters)-1,dtype = numpy.int16)
>>> Shifts
array([0, 0, 0, 0], dtype=int16)

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采纳的回答

Stephen23
Stephen23 2019-5-29
编辑：Stephen23 2019-5-29
You need to read the numpy zeros documentation, because your syntax does not actually match its specification:
import numpy as np
Filters = [1,2,3];
Shifts = np.zeros((len(Filters)-1,1),dtype=np.int16)
% ^ ^ The shape needs to be ONE iterable!
Most likely you do not need a 2D numpy array, and a simple 1D array would suffice:
Shifts = np.zeros(len(Filters)-1,dtype=np.int16)

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