How can I solve if condition in for loop matrix?

Question

Dina Maulina 2019-5-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/464746-how-can-i-solve-if-condition-in-for-loop-matrix

评论： Dina Maulina 2019-6-28

I want to make an iteration that when the component of a matrix A has less value than the component of matrix B, it will continue the process to the next iteration.

A =

[ 2 5 9 12

6 4 13 1

3 2 19 5]

B=

[ 5

5

5]

in the first column, the condition is not met so it cannot proceed to the second column. and in the second column, conditions have been met so that it can proceed to the third column.

I tried in for loop but, the A values always stuck in first column even condition is right.

Thank you.

3 个评论
显示 1更早的评论隐藏 1更早的评论

Dina Maulina 2019-5-30

What I want is when the all of the A component value <= B, then the loop will continue to the next column.

Guillaume 2019-5-30

then the loop

What loop? Remember that we have no idea what you're doing. If you don't show us your code, how can we tell us how to fix it?

Most likely, whatever loop you're using is not even necessary.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Murugan C 2019-5-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/464746-how-can-i-solve-if-condition-in-for-loop-matrix#answer_377191

编辑：Guillaume 2019-5-30

在 MATLAB Online 中打开

Hi

use below code for your query.

Here, B will check all rows, each column in A is less than, then it will allow to next iteration.

A = [ 2 5 9 12;  6 4 13 1;  3 2 19 5]
B = [5; 5 ;5];
[row,col] = size(A);
for ii = 1 : col
%     fprintf('Current Column is : %d\n', ii);
    C1 = A(:,ii) < B;
    if all(C1,1)
        fprintf('Current Column is : %d, Next Column is : %d\n', ii, ii+1);
        continue;
    else
        fprintf('Stopped at %d Column because unsatisfied B input \n', ii);
        break;
    end
end 