How to define a piecewise anonymous function

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Stephan
Stephan 2019-5-31
评论： Roy Goodman 2025-10-30
Hello everyone,
the example code
syms x
continuous_function = x^2+x;
matlabFunction(continuous_function,'Vars',x)
gives me the anonymous function
@(x)x+x.^2
I would like a similar result for piecewise functions. However, the code
syms x
piecewise_function = piecewise( 0<x<1, x, 'otherwiseVal', 0 );
matlabFunction(piecewise_function,'Vars',x)
does not work.
Thanks for any help!

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采纳的回答

Star Strider
Star Strider 2019-5-31
You need to use ‘logical indexing’:
piecewise_function = @(x) (x.^2+x) .* ((0<x) & (x<1));
x = linspace(-1, 2);
figure
plot(x, piecewise_function(x))
producing:
How to define a piecewise anonymous function - 2019 05 31.png
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Walter Roberson
Walter Roberson 2025-10-29
Ran in:
syms x
f = piecewise((0<=x) & (x<=1),x.^2+x,nan)
f = 
piecewise_function = matlabFunction(f, 'file', 'test_piecewise.m')
piecewise_function = function_handle with value:
@test_piecewise
dbtype test_piecewise
1 function f = test_piecewise(x) 2 %TEST_PIECEWISE 3 % F = TEST_PIECEWISE(X) 4 5 % This function was generated by the Symbolic Math Toolbox version 25.2. 6 % 29-Oct-2025 22:14:42 7 8 t2 = ((0.0 <= x) & (x <= 1.0)); 9 if ~all(cellfun(@isscalar,{t2})) 10 error(message('symbolic:sym:matlabFunction:ConditionsMustBeScalar')); 11 end 12 if (t2) 13 f = x+x.^2; 14 else 15 f = NaN; 16 end 17 end
x = linspace(-1, 2);
plot(x, arrayfun(piecewise_function, x))
xline([-1 2])
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更多回答（1 个）

Walter Roberson
Walter Roberson 2020-5-16
If you use matlabFunction with 'file' option, then it will convert piecewise() into if/else in the generated code.
Note: because it uses if/else instead of logical indexing, the generated code will not be vectorized on that variable.

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