Calculator with arithmetic sequences as input values

2 次查看（过去 30 天）
Aleksej R
Aleksej R 2019-5-31
评论： Geoff Hayes 2019-5-31
Hello,
I'm writing because I can not figure out how to solve the problem.
I have created a calculator to calculate the force at a certain depth, now I'm trying to make make it show different values at different depths.
The values for imput are Minimum depth of a hole, maximum depth and the common difference alongside other constants.
I want it to calculate the force for every value and show values of all the forces.
Example: Minimum depth=1mm ; Maximum depth=5mm; Common difference=1mm.
F=H*a*b; where H is the depth, F is the force and a and b are the constants.
Force (at 1mm)= 100N ; Force (at 2mm) = 200N ; Force (at 3mm) = 300N ...
I have tried it with the for loop, but I had no luck.
I would be very grateful for any help.
  3 个评论
显示 1更早的评论
Aleksej R
Aleksej R 2019-5-31
Hello,
In the first version of the calculator I only had the H which was THE depth. This was the only variable.
So the input values were for example: Depth (H), speed (constant),.... With this version I could only get one result (one force value).
But in the second version I have to make Hmin, Hmax and the common difference.
So it will be: Minimum depth (Hmin), Maximum depth (Hmax) and the common difference (let's say its symbol is D).
Geoff Hayes
Geoff Hayes 2019-5-31
ok...so perhaps the following will help (I'm guessing as to your intentions of the minimum, maximum, and commond difference)
a = 42; % dummy value
b = 2; % dummy value
minDepth = 1;
maxDepth = 5;
commonDiff = 1; % your step size (?)
F = zeros(5,1);
k = 1;
for h = minDepth:commonDiff:maxDepth
F(k) = h*a*b;
k = k + 1;
end

请先登录，再进行评论。

请先登录，再回答此问题。

回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品


版本

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by