How to simplify this If command?
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I have a string of 36 numbers that I am reading in from a file and each number means something specific. I am trying to write a for loop/if statement combo that reduces the amount of arguments I need within the if statement and then stores it into a struct that I'll later make into a table. I know that I am reading in the data fine and that my varible "s" is the correct string of numbers, but once I enter the for loop I skip over the if statement entirely and display "Inside For" 35 times with no other result. Is there a way to avoid having to state if i == 1 || i == 4....etc? So far my code is as follows:
s = textscan(sentence.data,'%d%d%d%d%f%f%f%d%f%f%f%d%f%f%f%d%f%f%f%d%f%f%f%d%f%f%f%d%f%f%f%d%f%f%f%d','Delimiter',',');
for i = [1:36]
disp('Inside For...'); %these display functions are to check my work
if i == [1:3:36]
disp('Inside IF...'); %never get this message
carnum = s(i);
speed = strcat('car ', carnum, ' speed');
struct(c).(speed) = s(i+1);
struct(c).carnum = carnum;
end
end
采纳的回答
Star Strider
2019-6-3
Example:
for i = 1:36
if any(i == 1:3:36)
fprintf('1 = %d\n',i)
end
end
illustrates the idea and the result.
2 个评论
Ryan Revering
2019-6-3
Star Strider
2019-6-3
As always, my pleasure.
My demonstration loop worked without problems.
I suspect the problem is the way textscan returns its results.
Note that (from the documentation):
and ‘C’ is usually a (1x1) cell.
You have several options, one being to address individual elements of ‘C’, using the techniques in: Access Data in Cell Array (link), or using the cell2mat (link) function to transform it into a matrix. (I prefer using cell2mat.) Note that you then need to be more specific about what field (likely column) of the matrix you assign to ‘carnum’.
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